International Journal of Statistics and Applications
p-ISSN: 2168-5193 e-ISSN: 2168-5215
2018; 8(5): 267-273
doi:10.5923/j.statistics.20180805.05

A. J. Saka1, B. L. Adeleke2, T. G. Jaiyeola1
1Department of Mathematics, Obafemi Awolowo University, Ile Ife, Nigeria
2Department of Statistics, University of Ilorin, Ilorin, Nigeria
Correspondence to: A. J. Saka, Department of Mathematics, Obafemi Awolowo University, Ile Ife, Nigeria.
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Copyright © 2018 The Author(s). Published by Scientific & Academic Publishing.
This work is licensed under the Creative Commons Attribution International License (CC BY).
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This paper presents, a new method of constructing nested balanced incomplete block designs (NBIBDs) of resolvable type called Coset-k2, using an algebraic notion, of the left coset type. The class of NBIBDs that was constructed for
treatments arranged in ‘b’ blocks of size
each with
and other parameters of the design are expressed as
Indeed, the parameters of the design for any given number of treatments, v, are specified with ease even before the full designs are constructed. Also, fewer numbers of blocks are required when compared with the designs of comparable sizes. Designs that are constructed in this paper are appropriate for experiments where extraneous factors of two types if they exist can be eliminated, evaluated and controlled.
Keywords: Coset, Resolvable Designs, Incomplete Block Designs, Nested Designs and Nested Balanced Incomplete Block Designs
Cite this paper: A. J. Saka, B. L. Adeleke, T. G. Jaiyeola, Coset-k2 Nested Balanced Incomplete Block Designs of Resolvable Type, International Journal of Statistics and Applications, Vol. 8 No. 5, 2018, pp. 267-273. doi: 10.5923/j.statistics.20180805.05.
The parameters of the design are:v = 7, k = 3, b = 35, r = 15, λ = 5.The corresponding reduced BIBD of example 3 is as presented as example 4 below: Example 4 Reduced BIBD from unreduced BIBD in Example 3:(1, 2, 4)(1, 3, 7)(1, 5, 6)(2, 3, 5)(2, 6, 7)(3, 4, 5)(4, 5, 7)The parameters of the resulting reduced design are:v = 7, k = 3, b1 = 7, r1 = 3, λ1 = 1which satisfies the necessary conditions for the existence of BIBDs.
Let R be an equivalence relation on a set X and let x ϵ X. Then [x] = {y ϵ X : yRx} is called the equivalence class of x.Theorem 3 Fundamental Theorem of Equivalence Relation Given an equivalence relation R on a set X, the equivalence classes of X form a partition of X. Conversely, if P = {Xi}iϵΩ is a partition of a set X, then there is an equivalence relation on X with equivalence classes Xi.
satisfy the following relation.![]() | (1) |
be a sub-block (generator) defined as H = {nk \ n = 1,…, k}, then i + H = {(i+h)(mod v)lh ϵ H}, i = 1, … k, with v( mod) = v, where k2, is called a coset of H in ℕ by i ϵ N. The family {i + H}ki=1 is called the coset initial block of H in N. Let
be the group of integers modulo k2,
with a subgroup H = {nk n = 1, 2,…, k}. Then(i)
is a coset of H in
(ii)
is a Coset Initial Block of H in
Proof: For k = 2,3,4 are illustrated below in cases 1,2 and 3 respectively.
The initial main-block for NBIBD for v = 4, k = 2, is [(3, 1), (4, 2)].
The initial main-block for NBIBD for v = 9, k = 3, is [(4, 7, 1), (5, 8, 2), (6, 9, 3)].
The initial main-block for NBIBD for v = 16, k = 4, is [(5, 9, 13, 1), (6, 10, 14, 2), (7, 11, 15, 3), (8, 12, 16, 4)].Case 4: Let k = m, v = [1, 2, …, m2], H = {mn : n = 1, …, m} = {m, 2m, 3m, …, (m – 5)m, (m – 4)m, (m – 3)m, (m – 2)m, (m – 1)m, m2}. The sub-blocks which form the initial main-block are shown in Figure 1.Case 5: Consider k = m + 1, v = [1, 2, …, (m + 1)2], H = {(m + 1)n : n = 1, …, m + 1} = {m + 1, 2(m + 1), 3(m + 1), …, (m - 1)(m + 1), m(m + 1), (m + 1)2}. The sub-blocks which form the initial main-block are shown in Figure 2.The entries in the matrix in Figure 1 marked with a unique colour in diagonal lines correspond with entries in the matrix in Figure 2 marked with the same unique colour of horizontal lines in the appropriate direction of sequence. Entries in the last column of the matrix in Figure 1 correspond to the entries in the last column of matrix in Figure 2, except the entry
in the last row; which corresponds to the entry in the row 1, column 1 of the matrix in Figure 1. All entries in the matrix of Figure 1 can be found in the matrix of Figure 2. However, the converse is not true because entries in the third and second to the last columns (except one entry
) of the matrix in Figure 2 are not in the matrix in the Figure 1. These entries are
and
All these entries are distinct and greater than
Thus, when
we have a Coset Initial Block of
. So, when
we equally have a Coset Initial Block of 
![]() | Figure 1. Proof of Theorem 4 for k=m |
![]() | Figure 2. Proof of Theorem 4 for k = m+1 |
be a given treatment
and let
be partitions of X such that for the sub blocks 

Then
is a Nested Balanced Incomplete Block Designs (NBIBD) of resolvable type with; treatment
, sub-block size
and parameter combinations 
Proof: Consider the pair
where X = {1, 2, …, K2} and
such that
is a partition of X for each
Consider the pair
where
such that
is a block design because X is a set of elements called points and
is a collection of non-empty subsets
of 2X called blocks. Since
for each
then
is a complete block design with 
Consider the pair
where X = {1, 2, …, k2} and
.
is a block design because
is a collection of non-empty subset
,
of X called sub-blocks. Recall that 
partitions X for each
This implies
for each
Thus,
for each
i.e
hence,
is an Incomplete Block Design. Also, since
for each 
appears once for 
That is the numbers of pair of treatments is one (λ = 1). Thus,
is a BIBD with
Since
partition X for each
distinctly, then if
then
Let
be the equivalence relation corresponding to partition
based on Theorem 3, then
Consider another partition
of X. If 
then
and so
and
i.e
are not disjoint which is a contradiction. Thus
whereas 
for any
. Hence, the pair
, appears once whereas

. So,
is a BIBD. Now, the Nested Block design
is a Nested Balanced Incomplete Block Design (NBIBD) of a Resolvable type with parameters 
Theorem 6: Let
and let
modulo k2 with
, i = 2, …, k+1 as partitions of
such that for the blocks
Then
is a Coset-k2 Nested Balanced Incomplete Block Designs (NBIBD) of Resolvable type with block size
and treatment
with parameters 
Proof: This is achieved by using Theorem 4 and Theorem 5. By Theorem 4,
is a partition of X and so by Theorem 5,
is a
Nested Balanced Incomplete Block Designs (NBIBD) of Resolvable type with block size
and treatment
, With parameters 

![]() | (2) |
denotes the number of treatments, b number of blocks in the experiment, k size of each block (number of treatment per block), r number of replications for a given treatment in the experiment, λ number of times each pair of treatment appear (occur) together in the experiment, N total number of plots (observations), b1 number of main-blocks in the experiment, b2 number of sub-blocks in the experiment, k1 size of each main-block (number of treatment per main-block), k2 size of each sub-block (number of treatment per sub-block), λ1 number of times each pair of treatment appear (occur) together in the main-blocks, λ2 number of times each pair of treatment appear (occur) together in the sub-blocks and m number of sub-blocks within the main block.Meanwhile, the relationships among the design parameters given above are presented below. ![]() | (3) |
![]() | (4) |
![]() | (5) |
The corresponding parameters of the reduced form are obtained as follows: Let f = gcd(b, r, λ) = 7, thenb1 = b/f = 84/7 = 12, r1 = r/f = 28/7 = 4, λ1 = λ /f = 7/7 = 1[(4, 7, 1), (5, 8, 2), (6, 9, 3)][(4, 5, 6), (7, 8, 9,),(1, 2, 3)][(1, 6, 8), (2, 4, 9), (3, 5, 7)][(1, 5, 9), (2, 6, 7), (3, 4, 8)]The parameters of the design are:V = 9, r = 4, b1 = 4, k1 = 9, λ1 = 4, b2 = 12, k2 = 3, λ2 = 1Design 3: A resolvable NBIB design v = 16, k = 4
The corresponding parameters of the reduced form are obtained as follows: Let f = gcd(b, r, λ) = 91, thenb1 = b/f = 1820 / 91 = 20, r1 = r / f = 455/91 = 5,λ1 = λ /f = 91/91 = 1[(5, 9, 13, 1), (6, 10, 14, 2), (7, 11, 15, 3), (8,12 , 16, 4)][(5, 6, 7, 8), (9, 10, 11, 12), (13, 14, 15, 16), (1, 2, 3, 4)][(1, 6, 11, 16), (2, 5, 12, 15), (3, 8, 9, 14), (4, 7, 10, 13)][(1, 7, 12, 14), (2, 8, 11, 13), (3, 5, 10, 16), (4, 6, 9, 15)][(1, 8, 10, 15), (2, 7, 9, 16), (3, 6, 12, 13), (4, 5, 11, 14)]The parameters of the design are:v = 16, r = 5, b1 = 5, k1 = 16, λ1 = 5, b2 = 20, k2 = 4, λ2 = 1Design 4: A resolvable NBIB design v= 25, k = 5
The corresponding parameters of the reduced form are obtained as follows: Let f = gcd(b, r, λ) = 1771, thenb1 = b/f = 53130/1771 = 30, r1 = r/f = 10626/1771 = 6, λ1 = λ /f = 1771/1771 = 1 [(6, 11, 16, 21, 1), (7, 12, 17, 22, 2), (8, 13, 18, 23, 3), (9, 14, 19, 24, 4), (10, 15, 20, 25, 5)][(6, 7, 8, 9, 10), (11, 12, 13, 14, 15), (16, 17, 18, 19, 20), (21, 22, 23, 24, 25), (1, 2, 3, 4, 5)][(1, 7, 13, 19, 25), (2, 10, 14, 16, 23), (3, 9, 12, 20, 21), (4, 6, 15, 18, 22), (5, 8, 11, 17, 24)][(1, 8, 14, 20, 22), (2, 9, 11, 18, 25), (3, 7, 15, 16, 24), (4, 10, 13, 17, 22), (5, 6, 12, 19, 23)][(1, 9, 15, 17, 23), (2, 6, 13, 20, 24), (3, 10, 11, 19, 22), (4, 8, 12, 16, 25), (5, 7, 14, 18, 21)][(1, 10, 12, 18, 24), (2, 8,15, 19, 21), (3, 6, 14, 17, 25), (4, 7, 11, 20, 23), (5, 9, 13, 16, 22)]The parameters of the design are:v = 25, r = 6, b1 = 6, k1 = 25, λ1 = 6, b2 = 30, k2 = 5, λ2 = 1Design 5: A resolvable NBIB design v = 49, k = 7
Let f = gcd(b, r, λ) = 1533939, then
[(8, 15, 22, 29, 36, 43, 1), (9, 16, 23, 30, 37, 44, 2), (10. 17, 24, 31, 38, 45, 3), (11, 18, 25, 32, 39, 46, 4), (12, 19, 26, 33, 40, 47, 5), (13, 20, 27, 34, 41, 48, 6), (14, 21, 28, 35, 42, 49, 7)] [(8, 9, 10, 11, 12, 13, 14), (15, 16, 17, 18, 19, 20, 21), (22, 23, 24, 25, 26, 27, 28), (29, 30, 31, 32, 33, 34, 35), (36, 37, 38, 39, 40, 41, 42), (43, 44, 45, 46, 47, 48, 49), (1, 2, 3, 4, 5, 6, 7)][(8, 16, 24, 32, 40, 48, 7), (15, 23, 31, 39, 47, 6, 14), (22, 30, 38, 46, 5, 13, 21), (29, 37, 45, 4, 12, 20, 28), (36, 44, 3, 11, 19, 27, 35), (43, 2, 10, 18, 26, 34, 42), (1, 9, 17, 25, 33, 41, 49)][(8, 23, 38, 4, 19, 34, 49), (15, 30, 45, 11, 26, 41, 7), (22, 37, 3, 18, 33, 48, 14), (29, 44, 10, 25, 40, 6, 21), (36, 2, 17, 32, 47, 13, 28), (43, 9, 24, 39, 5, 20, 35), (1, 16, 31, 46, 12, 27, 42)][(8, 30, 3, 25, 47, 20, 42), (15, 37, 10, 32, 5, 27, 49), (22, 44, 17, 39, 12, 34, 7), (29, 2, 24, 46, 19, 41, 14), (36, 9, 31, 4, 26, 48, 21), (43, 16, 38, 11, 33, 6, 28), (1, 23, 45, 18, 40, 13, 35)][(8, 37, 17, 46, 26, 6, 35), (15, 44, 24, 4, 33, 13, 42), (22, 2, 31, 11, 40, 20, 49), (29, 9, 38, 18, 47, 27, 7), (36, 16, 45, 25, 5, 34, 14), (43, 23, 3, 32, 12, 41, 21), (1, 30, 10, 39, 19, 48, 28)][(8, 44, 31, 18, 5, 41, 28), (15, 2, 38, 25, 12, 48, 35), (22, 9, 45, 32, 19, 6, 42), (29, 16, 3, 39, 26, 13, 49), (36, 23, 10, 46, 33, 20, 7), (43, 30, 17, 4, 40, 27, 14), (1, 37, 24, 11, 47, 34, 21)][(8, 2, 45, 39, 33, 27, 21), (15, 9, 3, 46, 40, 34, 28), (22, 16, 10, 4, 47, 41, 35), (29, 23, 17, 11, 5, 48, 42), (36, 30, 24, 18, 12, 6, 49), (43, 37, 31, 25, 19, 13, 7), (1, 44, 38, 32, 26, 20, 14)]The parameters of the design are:v = 49, r = 8, b1 = 8, k1 = 49, λ1 = 8, b2 = 56, k2 = 7, λ2 = 1