International Journal of Theoretical and Mathematical Physics
p-ISSN: 2167-6844 e-ISSN: 2167-6852
2013; 3(1): 10-25
doi:10.5923/j.ijtmp.20130301.03
Vasil G. Angelov
Department of Mathematics, University of Mining and Geology “St. I. Rilski”, Sofia, 1700, Bulgaria
Correspondence to: Vasil G. Angelov , Department of Mathematics, University of Mining and Geology “St. I. Rilski”, Sofia, 1700, Bulgaria.
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Copyright © 2012 Scientific & Academic Publishing. All Rights Reserved.
The paper deals with an analysis of transmission line terminated by in series connected RL-loads parallel to C-load. The mixed problem for Telegrapher equations to a periodic problem on the boundary is reduced. The obtained neutral system of equations in an operator form is presented. The fixed points of the operator in question are solutions of the periodic problem.
Keywords: Lossless Transmission Lines, RLC-Loads, Periodic Solutions, Fixed Point Theorems
Cite this paper: Vasil G. Angelov , Lossless Transmission Lines Terminated by in-Series Connected RL-Loads Parallel to C-Load, International Journal of Theoretical and Mathematical Physics, Vol. 3 No. 1, 2013, pp. 10-25. doi: 10.5923/j.ijtmp.20130301.03.
into itself. The second one is to show that B is contractive operator. The fixed point of B is the required periodic solution. The numerical example in 2.6 shows that for applications are required only inequalities obtained in the proof of the main theorem.
be the length of the transmission line and
, where L is per unit length inductance and C – per unit-length capacitance. In accordance of Kirchoff’s voltage-law (Figure 1) we have to add the voltages of the elements
and
after that to define the current of
and finally to add it with the current of
. In the real cases parallel to
and
is connected an input voltage
, where
is the amplification coefficient. Since we have to add the currents one can replaced
by an equivalent current source
. We assume that the second end is terminated by the same configuration.Assume that
and
are nonlinear elements, that is,
and
are nonlinear functions. So we have 
and then 
![]() | Figure 1. Lossless transmission line terminated at both ends by in series connected RL-loads parallel to C-load |
is connected parallel to RL-elements then Kirchoff’s current-law yields ![]() | (1) |
then
can be found as a solution of differential equation
But
is unknown too and then from (1) we have
or one more differential equation:
Analogously for the right end we have
Now we are able to formulate the initial-boundary value (mixed) problem for the transmission line equations: to find a solution
of the first order partial differential system of hyperbolic type ![]() | (2) |
satisfying the initial conditions![]() | (3) |

![]() | (4) |

![]() | (5) |
![]() | (6) |
![]() | (7) |
we get:![]() | (8) |
and hence
It follows ![]() | (9) |
and
we have
Replace them in (4) and (5) we obtain
and
But
We assume that the unknown functions are
and then in view of
solve with respect to the derivatives we reach the system ![]() | (10) |
So we have obtained a neutral system of differential equations with retarded arguments.
, for
where
have a strictly positive lower bounds. Put
..Then
For the I-V characteristics we assume
Then
. For
we get
Assumptions (L): 
Assumptions (C): 
For the V-I characteristics we assume that they are of polynomial type:
We introduce the sets for the unknown functions
where
is the set of all continuously differentiable
-periodic functions and
are positive constants (chosen below) and
Introduce the metrics
The set
turns out into a complete metric space with respect to the metric:
-periodic solution
of the system (10) on the interval
coinciding with prescribed
-periodic initial functions
on the interval respectively:
Remark 1. As in[3] one can shift the initial function of the mixed problem from the interval
along the characteristic to the interval
The main difficulty is to define a suitable operator whose fixed points are solutions sought. We define it in the following way: the four-tuple functions
are defined on every interval
(for every k = 0,1,2, …, m-1) by the expressions 
and
are translated to the right initial functions
over
.From now on the following assumptions will be fulfilled:(E):
(IN):
It follows
Lemma 1. If (E) and (IN) are satisfied and
then
are
-periodic ones.Lemma 2. If
then
The proofs can be accomplished as in[5],[6].The following lemma guaranties that the fixed points of the above defined operator are periodic solutions of the neutral system (10).Lemma 3. The periodic problem (10) has a solution 
that is,
Proof: Let
be a
-periodic solution of (10). Then after integration of the first equation we have (recall that
):
Therefore
Analogously we obtain
that is,
is a fixed point of B.Conversely, let
have a fixed point
Then
If we assume
in view of
one obtains a contradiction. It follows
Analogously
Consequently
Differentiating the last equalities we conclude that (10) has
-periodic solution.Lemma 3 is thus proved.
maps
into itself. Indeed
We have
Further on we have
and
and
On the other hand
We have
Then
Finally 
and
It remains to obtain the Lipschitz estimates for the right-hand sides of the equations. Omitting calculation of the partial derivatives we obtain:
Then
It follows
Further on we get

It follows
For the third component we obtain:

For the fourth component we have
It follows
For the derivatives we obtain
Consequently
Further on we have
ThereforeConsequently
Further on we have
Then
For the last component of the derivative we obtain
and
On the other hand
Consequently
.Finally we have
where
Then B has a unique fixed point which is a periodic solution of (10).Theorem 1 is thus proved.


Then
.Let us check the propagation of waves with
. We have
We choose
, then
and
.We choose resistive elements with the following V-I characteristics
and inductive elements with
Then
For
one obtains 
.Let us take 
where
. Let us choose
and
. Then 

.Then the above inequalities for 
become:



We calculate just
since
are of order
:
;
;
;
.