Electrical and Electronic Engineering
p-ISSN: 2162-9455 e-ISSN: 2162-8459
2012; 2(1): 6-10
doi:10.5923/j.eee.20120201.02
S. V. N. L. Lalitha1, Maheswarapu Sydulu2
1EEE Department, K L University, Guntur, Andhra Pradesh, 522502, India
2EEE Department, National Institute of Technology, Warangal, Andhra Pradesh, 506004, India
Correspondence to: S. V. N. L. Lalitha, EEE Department, K L University, Guntur, Andhra Pradesh, 522502, India.
| Email: | ![]() |
Copyright © 2012 Scientific & Academic Publishing. All Rights Reserved.
Fair allocation of transmission loss among market participants is essential in the present restructured electricity markets. This paper proposes a direct method to find the loss allocation. The methodology is based on simple circuit laws and does not involve any assumptions. Considering the real power injection and real power loss contribution factors loss allocation can be done. Case study of the proposed loss allocation methodology is conducted on an IEEE 14 bus system. Results are compared with the results of the existing methods in the literature.
Keywords: Load flow, network usage, Transmission Pricing, Zbus, transmission loss allocation
Cite this paper: S. V. N. L. Lalitha, Maheswarapu Sydulu, A Direct Method for Transmission Loss Allocation, Electrical and Electronic Engineering, Vol. 2 No. 1, 2012, pp. 6-10. doi: 10.5923/j.eee.20120201.02.
![]() | Figure 1. Π- Equivalent circuit of line |
and half line charging susceptance
connected between the buses
and
is shown in Fig. 1.
and
represent the nodal voltages of buses j & k respectively.From the load flow solution we can write expression for the complex line flow Sjk in terms of the node voltage Vj and the line current Ijk through the line
as![]() | (1) |
![]() | (2) |
![]() | (3) |
![]() | (4) |
from (4) in (1) and rearranging ![]() | (5) |
![]() | (6) |
through any line j→k is represented as a function of the all bus currents; i = 1, 2, 3…..n.
represents contribution of ith bus to j→k line power flow.
can be expressed as ![]() | (7) |
![]() | (8) |
represents contribution of ith bus to k→j line complex power flow i.e counter flow. It is a well established fact that, Complex line loss in any line is the algebraic sum of active and counter complex line flows. Hence, we can write ![]() | (9) |
![]() | (10) |
is that it represents the contribution of ith bus to the j→k line loss and also the contribution of line j→k to the power injection at bus i. For a given power flow solution this quantity is a constant.Worked ExampleThe methodology is explained with the help of a Six bus system [10]. Two generators (located at buses 1 and 2) supply the power demand (located at buses 3, 5 and 6), while bus 4 is a zero injection (transfer) bus.The total real power loss in the system 8.37 MW is allocated among all 6 buses using the proposed method and its results are compared with those of the results obtained from existing methods in the literature.Base case bus voltages are obtained from N-R load flow solution for a six bus system whose line and bus data is shown in Tables 1 & 2At this stage, a new table is formed as shown in Table 3 and designated as [B] matrix. From close observation of the elements of Table 3, it is noticed that the algebraic sum of all elements in any row, say ith row, gives the “real power injection” at that bus i.e. ith bus power injection. Here, positive sign indicates the power generation and negative sign indicates the power demand. Further, it is to be noted that algebraic sum of all elements in any column, say lth column, gives the real power loss
in the transmission line corresponding to that column i.e lth line. This table is useful for dual purposes i.e. transmission loss as well as cost allocations. It has been arrived at without any assumptions and the results are highly reliable.Now, using the [B] matrix, transmission line real power loss allocation among all buses can be done in the following manner.
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![]() | (11) |
![]() | (12) |
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![]() | (13) |
![]() | Figure 2. IEEE 14 bus system |
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