Quang Phung Duy
Department of Mathematics, Foreign Trade University, Ha noi, Viet Nam
Correspondence to: Quang Phung Duy , Department of Mathematics, Foreign Trade University, Ha noi, Viet Nam.
Email: |  |
Copyright © 2012 Scientific & Academic Publishing. All Rights Reserved.
Abstract
The aim of this paper is to give recursive and integral equations for ruin probabilities of generalized risk processes under assumption that both sequences of claims and rates of interest are homogenous Markov chains. Generalized Lundberg inequalities for ruin probabilities of these processes are derived by using recursive technique. Firstly, we give a recursive equations for finite – time probability and ultimate ruin probability. By using these equations, we can derive probability inequalities for finite – time probability and ultimate ruin probability. The above results give upper bounds for finite – time probability and ultimate ruin probability. A numerical example is given to illustrate results.
Keywords:
Integral equation, Recursive equation, Ruin probability, Homogeneous Markov chain
Cite this paper: Quang Phung Duy , Ruin Probability in a Generalized Risk Process under Rates of Interest with Homogenous Markov Chain Claims and Homogenous Markov Chain Interests, Applied Mathematics, Vol. 3 No. 5, 2013, pp. 185-197. doi: 10.5923/j.am.20130305.05.
1. Introduction
For over a century, there has been a major interest in actuarial science. Since a large portion of the surplus of insurance business from investment income, actuaries have been studying ruin problems under risk models with rates of interest. For example, Teugels and Sundt[10],[11] studied the effects of constant rate on the ruin probability under the compound Poisson risk model. Yang[13] established both exponential and non – exponential upper bounds for ruin probabilities in a risk model with constant interest force and independent premiums and claims. Cai[3],[4] investigated the ruin probabilities in two risk models, with independent premiums and claims and used a first – order autoregressive process to model the rates of in interest. Cai and Dickson[5] obtained Lundberg inequalities for ruin probabilities in two discrete- time risk process with a Markov chain interest model and independent premiums and claims. In this paper, we study the models considered by Cai and Dickson[5] to the case homogenous Markov chain claims and homogenous Markov chain rates of interest and independent premiums. The main difference between the model in our paper and the one in Cai and Dickson[5] is that claims and rates of interest in our model are assumed to follow homogeneous Markov chains. We let
be premiums,
be claims,
be interests and they define on probability space
To establish probability inequalities for ruin probabilities of these models, we study two styles of premium collections. On the one hand of the premiums are collected at the beginning of each period then the surplus process
with initial surplus
can be written as | (1.1) |
which can be rearranged as | (1.2) |
On the other hand, if the premiums are collected at the end of each period, then the surplus process
with initial surplus
can be written as | (1.3) |
which is equivalent to | (1.4) |
where throughout this paper, we denote
and
if
.We assume that:Assumption 1.1.
Assumption 1.2.
is a sequence of independent and identically distributed non – negative continuous random variables with the same distributive function
.Assumption 1.3.
is a homogeneous Markov chain,
take values in a finite set of non - negative numbers
with
and
where
Assumption 1.4.
is homogeneous Markov chain,
take values in a finite set of non - negative numbers
with
and
where
Assumption 1.5.
and
are assumed to be independent.We define the finite time and ultimate ruin probabilities of model (1.1) with assumption 1.1 to assumption 1.5, respectively, by | (1.5) |
 | (1.6) |
Similarly, we define the finite time and ultimate ruin probabilities of model (1.3) with assumption 1.1 to assumption 1.5, respectively, by | (1.7) |
 | (1.8) |
In this paper, we derive probability inequalities for
and
. The paper is organized as follows; in Section 2, we give recursive and integral equations for
and
. In Section 3 we derive probability inequalities for
and
by an inductive approach. A numerical example is given to illustrate these results in Section 4. Finally, we conclude our paper in Section 5.
2. Integral Equation for Ruin Probabilities
We first give recursive equations for
and an integral equation for
.Theorem 2.1. If model (1.1) satisfies the assumptions 1.1 to 1.5 then for n = 1, 2, …  | (2.1) |
and | (2.2) |
Proof.Give
Let
,
.From (1.1), we have
and | (2.3) |
In addition, | (2.4) |
Let
be independent copies of
,
,
respectively with
Thus, (2.4) and (1.2) imply that | (2.5) |
On the other hand, (1.5) implies
Thus, we have | (2.6) |
From (2.3), we have
.From (2.5), we have
Therefore, (2.6) is written as | (2.7) |
Thus, the integaral equation for
in Theorem 2.1 follows immediately from the dominated convergence theorem by letting
in (2.7).This completes the proof Similarly, the following recursive equation for
and integral equation for
are hold.Theorem 2.2. If model (1.3) satisfies assumptions 1.1 to 1.5 then, for n = 1, 2, … | (2.8) |
and | (2.9) |
Next, we establish probability inequalities for ruin probabilities of model (1.1) and model (1.3).
3. Probability Inequalities for Ruin Probabilities
To establish probability inequalities for ruin probabilities of model (1.1), we first proof the following Lemma.Lemma 3.1. Let model (1.1) satisfy assumptions 1.1 to 1.5 and
. If, any
,
and | (3.1) |
then there exists a unique positive constant
satisfying: | (3.2) |
Proof.Define
We have
From
is discrete random variables and it takes values in
then
has
-th derivative function on
(any
).In addition,
with
satisfying :
and
.This implies that
has
-th derivative function on
with
. Thus,
has
-th derivative function on
with
and
.This implies that | (3.3) |
and | (3.4) |
By
, we can find some constant
such that
Then, we can get that
Imply | (3.5) |
From (3.3), (3.4) and (3.5) there exists a unique positive constant
satisfying (3.2).This completes the proof .Let:
Using Lemma 3.1 and Theorem 2.1, we obtain a probability inequality for
by an inductive approach.Theorem 3.1. If model (1.1) satisfies assumptions 1.1 to 1.5,
and (3.1) thenfor any
,
and 
 | (3.6) |
where
Proof.Firstly, we have
.For any
, we have | (3.7) |
 | (3.8) |
Then, for any
,
and
, we can write  | (3.9) |
Thus, combining (3.8) and (3.9), we have | (3.10) |
Applying an inductive hypothesis, we assume for any
,
and
, | (3.11) |
Then (3.10) implies that (3.11) holds with n = 1. For
,
and
, we have
where
,
and
For any

then
.That
then | (3.12) |
Therefore, by Lemma 3.1, (2.1), (3.7) and (3.12), we get
Thus
Consequently, for any
(3.11) holds. Therefore, (3.6) follows by letting
in (3.11).This completes the proof Remark 3.1. Let
. From
and
, we have
Therefore, upper bound for ruin probability in (3.6) is better than
.Similar to Lemma 3.1, we have Lemma 3.2.Lemma 3.2. Assume that model (1.3) satisfies assumptions 1.1 to 1.5 and
. If any
and
,
and  | (3.13) |
then there exists a unique positive constant
satisfying:
Let
Next, we use Lemma 3.2 and Theorem 2.2 to give a probability inequality for
by an inductive approach.Theorem 3.2. If model (1.3) satisfies assumptions 1.1 to 1.5,
and (3.13) then, for any
and 
 | (3.14) |
where
Proof.Similarly with Theorem 3.1, we have
and any 
 | (3.15) |
 | (3.16) |
Then, for any
,
and 
Hence | (3.17) |
Under an inductive hypothesis, we assume that  | (3.18) |
Then, (3.17) implies that (3.18) holds with n = 1. For
,
and
, we have
where
,
and
For any
then 

We get
then | (3.19) |
Therefore, by Lemma 3.2, (2.8), (3.15) and (3.19), we get
Thus
Consequently, for any n =1, 2, … (3.18) holds. Therefore, (3.14) follows by letting
in (3.18). Remark 3.2.Let
From
and
, we have
Hence, upper bound for ruin probability in (3.14) is better than
.
4. A Numerical Illustration
In this section we give a numerical example to illustrate the bounds of
derived in Section 3. Let
be a sequence of independent and identically distributed non-negative continuous random variables with the same distributive function
.Let
be a homogeneous Markov chain such that for any
,
take values in
with
having a distribution:
and matrix
is given by
Let
be a homogeneous Markov chain such that for any
,
take value in
with
having a distribution:
and matrix
is given by
Then, we have
Therefore | (4.1) |
In the other hand, | (4.2) |
and  | (4.3) |
Combining (4.1), (4.2) and (4.3) imply that Lemma 3.1 holds.Next, we solve equation (3.2). Firstly, we have
where
(
)and
Respective equation (3.2) for
, by | (4.4) |
 | (4.5) |
Using Maple, we find respective root of (3.2) for
, by
Hence,
.We can apply the result of Theorem 3.1 for 
 | (4.6) |
where
Table 1 shows values upper bounds
of
for a range of value of u
5. Conclusions
Our main results in this paper are Theorem 2.1 and Theorem 2.2 giving recursive equations for
and
and integral equations for
and
; Theorem 3.1 and Theorem 3.2 giving probability inequalities for
and
by an inductive approach. In addition, a numerical example is given illustrating Theorem 3.1.
ACKNOWLEDGMENTS
The author is thankful to the referee for providing valuable suggestions to improve the quality of the paper.In addition, the author would like to express his sincere gratitude to Professor Bui Khoi Dam for many scientific suggestions during the preparation of this paper.
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