Applied Mathematics
p-ISSN: 2163-1409 e-ISSN: 2163-1425
2012; 2(4): 100-115
doi: 10.5923/j.am.20120204.02
N. Sthanumoorthy , K. Priyadharsini
Ramanujan Institute for Advanced study in Mathematics, University of Madras, Chennai - 600 005, India
Correspondence to: N. Sthanumoorthy , Ramanujan Institute for Advanced study in Mathematics, University of Madras, Chennai - 600 005, India.
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Copyright © 2012 Scientific & Academic Publishing. All Rights Reserved.
In this paper, complete classifications of all BKM Lie superalgebras (with finite order and infinite order Cartan matrices) possessing Strictly Imaginary Property are given. These classifications also include, in particular, the Monster BKM Lie superalgebra.
Keywords: Borcherds Kac-Moody Lie Superalgebras, Strictly Imaginary Roots, Purely Imaginary Roots
be a finite index set and let
be an
real matrix. Let
be a subset of I. If A satisfies the following conditions, then
is called a BKM super matrix.
if
then 
if
and
then
Define, subsets
and
of I by
.Let
be a collection of positive integers such that
for all
We call
a charge of A.Also set
and
.Remarks: (1) If
is an empty set then the BKM super matrix coincides with the corresponding BKM matrix( or GKM matrix). (2) For description of the quasi- Dynkin diagram,
one can refer to[19]. A Generalized Generalized Cartan Matrix is called indecomposable if it cannot be reduced to a block diagonal form by shuffling rows and columns[8].For the sake of completeness we repeat the following fundamentals already explained in[17].Definition 2.1.2:[6] Let I be an index set.
be an indecomposable BKM super matrix where
and
. Then one and only one of the following three possibilities holds forA.(Fin) det
; there exists
such that
and
or
.(Aff) Corank =1; there exists
such that
and
(Ind) det
; there exists
such that
and
Referring to the above three cases, we say that A is of finite, affine or indefinite type respectively and write
or
respectively.Definition 2.1.3:[18]We say that a BKM super matrix
is of hyperbolic type, if it is indefinite type and every principal submatrix of A is either finite or affine type BKM super matrix.Definition 2.1.4[19]: If a BKM super matrix
decomposes as
where,
a diagonal matrix and
is a symmetric matrix, then A is said to be symmetrizable.If A is a symmetrizable BKM supermatrix, then taking the diagonal matrix D satisfying
by
we have
and
for all i and j.We assume that
is a symmetrizable and indecomposable BKM supermatrix.Definition 2.1.5:[19] For any BKM supermatrix,
where
, we have a triple
, where
and
satisfying the following relations: (i)
is a finite dimensional (complex) vector space such that
rank A. (ii)
is linearly independent and
is linearly independent, where
iii)
, where
denotes a duality pairing between
and
This triple
is called a realization of A.Call an element of
(respectively
) a fundamental root or a simple root (respectively fundamental coroot or a simple coroot).Moreover, set
and
. We call an element of
(resp.
) a real simple root (resp. an imaginary simple root).Also divide
as
, the set of all even simple roots and
, the set of all odd simple roots. Let
is the residue class ring mod 2 with elements
and
Definition 2.1.6:[19] A
-graded vector space
possessing the operation called the bracket product,
is called a Lie superalgebra if it satisfies the following conditions:
for all
.Definition 2.1.7:[19] The Borcherds Kac-Moody Lie superalgebra (abbreviated as BKM Lie superalgebra or BKM superalgebra)
associated to a symmetrizable BKM super matrix
is the Lie superalgebra generated by the vector space
and the elements
satisfying the following relations: 1.
2.
3.
4.
5. if
then
6. if
, then
7. if
then
. Remarks: As we are assuming that the matrix
is symmetrizable, the associated BKM superalgebra
is simple (for a proof one can see[6], and also[19] ),which we will denote by
. So for a BKM supermatrix
,
is called BKM Lie superalgebra or BKM superalgebra associated to
In[5], Dynkin diagrams were defined for Lie superalgebras. Dynkin diagrams were already extended from KM algebras to GKM algebras in[11] and then extended to BKM Lie superalgebras in[17], which are again given below.Definition 2.1.8:[17] To every BKM super matrix
, where
,
the index set I, is associated with a Dynkin diagram
defined as follows:
has n vertices and vertices i and j are connected by
number of lines if
and there is an arrow pointing towards i if
. If
, i and j are connected by a bold faced edge equipped with the ordered pair
Moreover 1. if
, the i-th vertex will be denoted by a white circle. 2. if
, the i-th vertex will be denoted by a white circle with (od) written within parentheses and below the circle to denote the vertex corresponding to an odd simple root in this case. 3. if
, the i -th vertex will be denoted by a crossed circle. 4. if
, the i -th vertex will be denoted by a crossed circle with (od) written within parentheses and below the circle to denote the vertex corresponding to an odd simple root in this case. 5. if
, the i -th vertex will be denoted by a white circle with
written within parentheses and above the circle. 6. if
, the i -th vertex will be denoted by a white circle with
written within parentheses and above the circle with (od) written within parentheses and below the circle to denote the vertex corresponding to an odd simple root in this case. With these definitions, the Dynkin diagrams of all BKM superalgebras can be drawn.Some examples of Dynkin diagrams of BKM superalgebras were drawn in[17].A BKM Lie superalgebra
, like a KM or BKM algebra, has the following natural root space decomposition:
where
is called the root space associated to
An element
is called a root, if
and
The number mult
is called the multiplicity of the root α. A root α of
can be expressed as
where
's are all
or all
. Corresponding to whether
's are all
or all
, α is called a positive root or a negative root respectively. Also
is called the height of α and is denoted by
We denote by
and
the set of all roots, positive roots and negative roots respectively. Also note that
and
.Definition 2.1.9:[19]Let
be a BKM Lie superalgebra. Set
and take a subspace
of
satisfying
.Define the symmetric bilinear form
on
as follows:
. Then
is non-degenerate on
and this induces the linear isomorphism,
We completely identify
and
via this map v and omit the symbol v in the following results. The proofs of these results are in[19].Lemma 2.1.10:[19] For
, one has the following:1.
2.
3.
4. If
then
, in particular if
, then
Remark: For
. In terms of inner product
, we have
and
.Definition 2.1.11:[17] For each
we define the simple reflection
by
The Weyl group W of
is the subgroup of
generated by the
's
. Note that
is a coxeter system. So for a real root
we define the reflection
of
with respect to α by
where
is the dual real root of
Note that
.Lemma 2.1.12:[19]. The bilinear form
on
and
is invariant under the action of the Weyl group.In particular, we have
for
Definition 2.1.13:[17]The set of all real roots of a BKM Lie superalgebra is defined as
Then the set of all imaginary roots is
We have,
and
.Definition 2.1.14:[19]Let
, then we have
. is called the root lattice and
is called the positive root lattice.The root lattice
becomes a (partially) ordered set by putting
for
.Now, for
, support of α is defined as
. If
is a connected subset of the Dynkin diagram of A, we say that
is connected.Definition 2.1.15:[19] Imaginary roots of BKM superalgebras are basically of two types, domestic-type and alien-type.Domestic-type imaginary root:An imaginary root which is conjugate to a fundamental root under the action of the Weyl group is called domestic-type imaginary root. We denote by
, the set of all domestic-type imaginary roots.Alien-type imaginary root:An imaginary root which is not a conjugate to a fundamental root under the action of the Weyl group is called alien-type imaginary root. We denote by
, the set of all alien-type imaginary roots.Since an imaginary root is either conjugate or not conjugate to a fundamental root under the action of Weyl group, each imaginary root is either domestic imaginary or alien imaginary.We have
Lemma 2.1.16:[19] 1.
is invariant under the action of the Weyl group. 2. If
then there exists
satisfying
3. For
Theorem 2.1.17:[19]For a symmetrizable BKM supermatrix
if we set
then concerning
and
we have the following results: 1.
. 2.
. where
and
Also by notation 
and
.Lemma 2.1.18:[19]For
and
one has the following: 1. The set
is a finite set. Let p be the minimum contained in this set, and let q be the maximum in this set. Then,
(c) the sequence
is bilaterally symmetric, and the left half of this sequence is monotone nondecreasing. Namely,1. 
Strictly domestic type imaginary roots, strictly alien type imaginary roots, strictly imaginary roots, purely imaginary roots, purely domestic type imaginary roots and purely alien imaginary root were already explained in[17]. We repeat the following definitions which we need here.Definition 2.1.19:[`17]A domestic-type imaginary root
in a BKM super algebra is said to be strictly domestic-type imaginary, if for every
either
or
is a root. Let
denote the set of all strictly domestic-type imaginary roots, positive and negative strictly domestic-type imaginary roots respectively.Definition 2.1.20:[17]An alien-type imaginary root
in a BKM super algebra is said to be strictly alien-type imaginary, if for every
either
or
is a root. Let
denote the set of all strictly alien-type imaginary roots, positive and negative strictly alien-type imaginary roots respectively.Definition 2.1.21:[17] An imaginary root
in a BKM super algebra is said to be strictly imaginary, if for every
either
or
is a root. The set of all strictly imaginary roots is denoted by
Let
denote the set of all strictly imaginary roots, positive and negative strictly imaginary roots respectively.Remark: As it was noticed in[5],(1)If
then
(2)
is a semigroup.Definition 2.1.22:[17] A BKM super matrix
is said to have strictly imaginary property, if
If a BKM supermatrix satisfies strictly imaginary property, we say that corresponding BKM Lie superalgebra satisfies strictly imaginary property.Purely alien imaginary roots, purely domestic imaginary roots were already explained in Sthanumoorthy et al.(2009).Definition 2.1.23:[17] Let
we say that α is purely imaginary, if for any
We say that the BKM super algebra
has the purely imaginary property, if
satisfies this property. We have,
Similarly we say that a negative root
is purely imaginary if
is a purely imaginary root. Denote by
and
Then, the set of all purely imaginary roots is
We omit the proof of the following theorem for BKM Lie superalgebras which can be directly verified using the proof for KM algebras already proved in[3].Theorem 2.1.24:[17] For BKM Lie superalgebras, the following results are true: (a) If
and
for all
then
(b) If
for all
then
(c) If
and
for all
then
for all
(d) If
then
(e)
is a semigroup. In addition to the above results, we prove the following results for BKM Lie superalgebras.Theorem 2.1.25: a) If
and
is connected, then
b) If
for all
then
Proof: a) Let
and
be connected. Then
So by lemma 2.1.18.
b) Let
. If
for all
then
or
So, by lemma 2.1.18., we have
or
Hence α is a strictly imaginary root.Remark:From the property
of the Theorem (2.1.24), we have
) if
Definition 3.1.2:[3]A is said to satisfy NC1, if there exists no subsets
such that
is affine or indefinite type, and
is decomposable.The following theorem proved by Casperson (1994) is for the indefinite Kac-Moody algebras possessing strictly imaginary property. Casperson (1994) gave a complete classification of Kac-Moody algebras possessing strictly imaginary property.Theorem 3.1.3:[3] A GCM lies in SIM if and only if it satisfies the condition NC1 and has no principal submatrix contained in the following list:1. The
matrices of the form
with
and
or
2. The matrices of the following Dynkin diagrams of twisted affine type:
3. The strictly hyperbolic
matrices associated with the Dynkin diagrams of the form:
4. The hyperbolic
matrices associated with the Dynkin diagrams of the form:
From[3], we can conclude the following for affine Kac-Moody algebras:5. If an algebra is affine, we have that
and hence
where
is the unique minimal positive imaginary root and k is the order of the diagram automorphism used to construct the algebra.Again for the case of
matrices, the following theorem gives a complete classification of the non-strictly imaginary roots:Theorem 3.1.4:[3]Suppose, for the GCM
,
, that
Then, either 1.
and
(or) 2.
where
and
Corollary 3.1.5:[3]The GCM
is not in SIM if and only if
and either
or
Proposition 3.1.6:[3] A GCM of affine type is a member of SIM if and only if it is of non-twisted affine type. Remarks:From[17], the set of all strictly imaginary roots of any BKM superalgebra is a subset of set of all purely imaginary roots, that is ,
may be an empty set or non-empty set depending upon the algebras. So, for the BKM superalgebras possessing purely imaginary property, we verify whether the set
is empty or not. In the case where
all purely imaginary roots are strictly imaginary as
is always true. BKM superalgebras which satisfy the condition
will be in the class of BKM algebras possessing strictly imaginary property.Hence the condition
is equivalent to
which is equivalent to SIM property.
(the symmetrizable GGX)
Here
are positive integers . Moreover, GX is KM matrix of finite, affine or indefinite type of order
and GGX is a supermatrix of finite, affine or indefinite type with r simple imaginary roots added to that of GX. Then the following results are true for BKM superalgebras with odd roots. 1. GX is of finite type: (a) If
with
(for all
) is true for all
then the corresponding BKM superalgebra satisfies SIM property.(b)If
with
in the above GGX for
is true for all
then the corresponding BKM superalgebra satisfies SIM property. Here in (a) and (b),
is the set of all odd roots and
is the set of all positive imaginary roots. 2. GX is of untwisted affine type: (a) If
with
(for all
) is true for all
then the corresponding BKM Lie superalgebra satisfies SIM property.(b)If
with
in the above GGX for
is true for all
then the corresponding BKM Lie superalgebra satisfies SIM property. 3. If GX is of twisted affine type, then Strictly imaginary property does not hold. 4. If GX is of indefinite type, then Strictly imaginary property does not always hold.Proof:In the usual notation, let
with
and
is the set of all simple roots with
is the set of all simple imaginary roots and
is the set of all simple real roots. Ingeneral
and
(1) Let GX be of finite type GCM and
be an positive imaginary root. Then
Here
We discuss below Case(a), Case(b) and Case(c) separately. Case(a): If
then we have
By Theorem 2.1.24.(a), it is clear that if
and
then Strictly imaginary property holds.Case(b): If
then
can be written as
Finally,
We divide this case(b) into Case(b)(1), Case(b)(2) (Case(b)(2)(i),Case(b)(2)(ii)) and Case(b)(3) separately.Case(b)(1): Let
We have
for
Since
s are always negative integers and
are always positive, by theorem 2.1.25., it is clear that
Case(b)(2):Let
Case(b)(2)(i): Let
with
If
by the theorem 2.1.25,
On the contrary, if
Then
As
is a real simple root,
This is also not true, because
are negative integers. So by theorem 2.1.25.,
Case(b)(2)(ii): Let
with
Then
But
Here
because
is a simple real root and
for
with
and
So
with
Hence by theorem 2.1.25.,
if
Case(b)(3):Let
We have
As all the
s are negative integers , by theorem 2.1.25.,
Case(c): If
then can be written as
Here
Finally,
We discuss below Case(c)(1), Case(c)(2) and Case(3) separately in Case(c).Case(c)(1): Let
We have
for
Since
s are always negative integers and
are always positive, by theorem 2.1.25., it is clear that
Case(c)(2): Let
Case(c)(2)(i):Let
with
If
then
We have,
But
As
is a real simple root with
This is not true, because
are negative integers. So by theorem 2.1.25.,
Case(c)(2)(ii): Let
with
Then
But
Here
because
is a simple real root and
for
with
and
So
with
By theorem 2.1.25.,
if
Case(c)(3):Let
We have
As all the
s are negative integers, by theorem 2.1.25.,
(2) Let GX be of untwisted affine type. For KM algebras of untwisted affine type, SIM property holds as per Casperson(1994). For BKM algebras with odd roots which we get as extensions of KM algebras untwisted affine type, the proof is exactly same to case(1) and hence SIM property holds.(3) Let GX be of twisted affine type. As per Casperson(1994) mentioned above, SIM property does not hold for KM algebras and the same is true for BKM Lie superalgebras which appear as extension of KM algebras of twisted affine type. Hence SIM property does not hold.(4)Let GX be of indefinite type. As far as indefinite BKM Lie superalgebras are concerned, extension of finite and untwisted affine type of KM algebras will hold SIM property, where as other algebras do not hold. The following example will illustrate the above theorem.Example: Extension of finite type Let
( the symmetrizable GGX)
This is a BKM supermatrix of indefinite type denoted by
, which is an extension of finite type
.If
and
then the Dynkin diagram can be drawn as follows: ![]() | Figure 1. Dynkin diagram of SBGA2 |
.
Here
Case(a):
. The following relations (i), (ii),...,(vii) can be directly verified.(i)If
with
then
(ii) If
with
then
(iii) If
with
then
(iv)If
with
then
(v)If
with
then
(vi)If
with
then
By Theorem 2.1.24., and from the above results (i), (ii), (iii), (iv), (v) and (vi), it is clear that if
and
that is if (in general),
then
for all
Case (b): Let
The following relations (i), (ii),...,(vi) can be easily verified. (i)If
we get
By Theorem 2.1.25., if
then
and
which implies
(ii) If
we get
(iii) If
we get
(iv) If
we get
(v) If
we get
(vi) If
we get
From the above results (ii), (iii), (iv), (v) and (vi) with
it is clear that
for
in (ii),
in (iii),
in (iv),
in (v),
in (vi). Hence, by Theorem 2.1.25., SIM property holds.In general, if
then
for
Case(c): Let
The following relations (i),(ii),...,(vi) can be directly verified.(i)If
we get
By Theorem 2.1.25., if
then
and
which implies
(ii) If
we get
(iii) If
we get
(iv) If
we get
(v)If
we get
(vi) If
we get
From the above results (ii), (iii), (iv), (v) and (vi) with
it is clear that
for
in (ii),
in (iii),
in (iv),
in (v),
in (vi). Hence, by theorem 2.1.25., SIM property holds. In general, for
SIM property holds if
Example: Extension of untwisted affine type Let
(the symmetrizable GGX)
This is a BKM supermatrix of indefinite type denoted by
, which is an extension of untwisted affine type
. If k=0,
and
then the Dynkin diagram can be drawn as follows:![]() | Figure 2. Dynkin diagram of SBGA1(1). |
Then
Here
Case(a):Let
The following relations (i),(ii), ....,(vi) can be easily verified.(i) If
with
and
then
(ii) If
with
and
then
(iii) If
with
and
then
(iv) If
with
and
then
(v) If
with
and
then
(vi)If
with
and
then
Similarly, we can find
for different
and
Hence by Theorem 2.1.24., and by the above results (i),(ii), ....,(vi) and others, it is clear that
for all
if
and
That is if
SIM property holds.Case(b): Let
The following relations (i), (ii),...,(iv) can be easily verified.(i)If
we get
By Theorem 2.1.25., if
then
which implies
(ii) If
we get
(iii) If
we get
we get 
Similarly, we can find
for
and
Hence by Theorem 2.1.25., and by the above results (ii), (iii) and others, with
it is clear that
for
,
,.....
In general, if
we get
for
Case(C): If
The following relations (i), (ii),...,(iv) can be easily verified.(i)If
we get
and
By Theorem 2.1.25., if
then
which implies
(ii) If
we get
(iii) If
we get
(iv)If
we get
Similarly, we can find
for
and
Hence by Theorem 2.1.25 and by the above results (ii), (iii),...,(iv) and others, with
it is clear that
for 

.....,
.....
In general, if
we get
for
Class(II): BKM Lie superalgebras of infinite order and with a finite non-empty set of odd roots We divide this class into three subclasses.(i) All simple roots are imaginary(odd or even)(ii) One simple real root(odd or even) and infinite number of imaginary roots(odd or even) (iii) Finite number of simple real roots and infinite number of imaginary roots.We discuss these cases below(i) All simple roots are imaginary(odd or even): For this class, all the roots are imaginary. So these algebras satisfy strictly imaginary property.(ii) One simple real root(odd or even) and infinite number of imaginary roots(odd or even): We prove the following theorem for this case. Theorem 3.2.2: Let
(the symmetrizable GGX)
Here
are positive integers and GGX is the BKM supermatrix with one real simple root and infinite number of imaginary roots. If
with
is true for all
then the corresponding BKM Lie superalgebra satisfies Strictly imaginary property.Proof:In the usual notation
with
and
with
and
We define
and
Let
and
. Then by Theorem 2.1.24.,
If
which is same as
then Strictly imaginary property holds.Remark: For BKM superalgebras which appear as extension of twisted affine type(Case 3) and extension of indefinite type(Case 4), examples were given in[17](
set)(Section 4, Case 3, subcase 2).Remarks:We have seen above that in the case of BKM Lie superalgebras of infinite order with one simple real root (odd or even ) and infinite number of imaginary roots (odd or even) for
SIM property holds only when
and
are all greater than one. As a counter example, we consider Monster Lie superalgebra with one simple real root and infinite number of simple imaginary roots(odd or even). Consider
with
and
for
(c(1): multiplicity of the root corresponding to -2 ). As
, the corresponding BKM Lie superalgebra does not satisfy SIM property. We prove this below. Consider Monster Lie superalgebra which has the following supermatrix as defined below: Let
be an index set and consider the Borcherds-Cartan super matrix
with charge
where
are the coefficients of the elliptic modular function
Here
is the BKM supermatrix and
We define
is the real root corresponding to the diagonal element 2 and
are the imaginary roots corresponding to the diagonal element -2 We consider any
then
This implies
does not satisfy the strictly imaginary property for
. Hence Strictly imaginary property does not hold for a Monster Lie superalgebra.(iii) Finite number(atleast two) of simple real roots and infinite number of imaginary roots: We prove the following theorem for this case. Theorem 3.2.3: Let
( the symmetrizable GGX)
Here
are positive integers and GGX is the BKM supermatrix with
real simple roots and infinite number of imaginary roots. If
with
is true for all
then the corresponding BKM Lie superalgebra satisfies Strictly imaginary property. Proof:In the usual notations
with
(
) and
Here,
the set of all simple roots with
the set of simple real root and
the set of all simple imaginary roots. We define
and
Let
and
As all
are negative integers and
we have
Hence
and SIM property holds.Remarks: As in the case of Monster Lie superalgebra with one simple real root and infinite number of imaginary simple roots with the condition
we can consider BKM Lie superalgebras with two simple real roots and infinite number of imaginary simple roots with the condition,
In this case, as
and for some
(similar to Monster Lie superalgebra as in theorem 3.2.3. ) SIM property does not hold . Hence we understand that for the infinite order case, the SIM property depends on the non-diagonal non-zero entries of the corresponding BKM supermatrix.