American Journal of Mathematics and Statistics
p-ISSN: 2162-948X e-ISSN: 2162-8475
2018; 8(4): 96-98
doi:10.5923/j.ajms.20180804.03

Rosemary Jasson Nzobo1, Benard Kivunge2, Waweru Kamaku3
1Pan African University Institute for Basic Sciences, Technology and Innovation, Nairobi, Kenya
2Department of Mathematics, Kenyatta University, Nairobi, Kenya
3Pure and Applied Mathematics Department, Jomo Kenyatta University of Agriculture and Technology, Nairobi, Kenya
Correspondence to: Rosemary Jasson Nzobo, Pan African University Institute for Basic Sciences, Technology and Innovation, Nairobi, Kenya.
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Copyright © 2018 The Author(s). Published by Scientific & Academic Publishing.
This work is licensed under the Creative Commons Attribution International License (CC BY).
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In this paper, we give general formulas for counting the number of levels, subgroups at each level and number of ascending chains of subgroup lattice of cyclic groups of order the product of distinct primes. We also give an example to illustrate the concepts introduced in this work.
Keywords: Lattice, Cyclic Group, Subgroups, Chains
Cite this paper: Rosemary Jasson Nzobo, Benard Kivunge, Waweru Kamaku, On the Lattice Structure of Cyclic Groups of Order the Product of Distinct Primes, American Journal of Mathematics and Statistics, Vol. 8 No. 4, 2018, pp. 96-98. doi: 10.5923/j.ajms.20180804.03.
where p is prime and k is a natural number) is a single chain. In [1], it was also shown that if G is a finite group and the subgroup lattice of G is a single chain, then G is cyclic. That is, a finite group has a single chain subgroup lattice if and only if it is isomorphic to
In [4], P'alfy showed that the subgroup lattice of a cyclic group
where n and m are distinct primes has two ascending chains and three levels. Furthermore, P'alfy argued that any group whose subgroup lattice is formed by two chains is isomorphic to
That is, a finite group has a subgroup lattice with two ascending chains if and only if it is isomorphic to
for primes
In this paper, we present general formulas for finding the number of levels, subgroups at each level and number of ascending chains of cyclic groups of order
where
are distinct primes.
is called a lattice if for every a,b in L, both
and
belong to L.2. The lattice whose elements are the subgroups of the group G with the partial order relation being set inclusion is called the subgroup lattice of the group G and is denoted by
.Definition 2.2 ([6]) Let G be a group. A sequence
of subgroups of G is called an ascending chain.Theorem 2.3 ([3]) Up to Isomorphism, there is exactly one cyclic group of order n.Theorem 2.4 ([2]) Isomorphic groups have the same subgroup lattice diagram.Theorem 2.5 ([5]) If
is a cyclic group of order n, then each subgroup of G has the form
where d is a unique positive divisor of n.Theorem 2.6 ([5]) In a finite cyclic group, each subgroup has order dividing the order of the group. Conversely, given a positive divisor of the order of the group, there is a subgroup of that order.Theorem 2.7 ([5]) If
is a cyclic group of order n and
are subgroups of G where
and
are positive divisors of n, then
iff
divides
.
where
are distinct primes and
are positive integers and let
be a subgroup lattice of G, then
has
.Proof: Every subgroup of G is of the form
where
Subgroups at
level are such that
The sum of these powers at the first, second to the last level are
respectively which form arithmetic progression
with the first term
, common difference
and the last term 
The number of levels,
is the number of terms of this
It follows that,
which gives
Remarks: Levels are counted from below, that is from the trivially group
to the group G.Corollary 3.2 If G is a cyclic group of order
where
are distinct primes and
is a subgroup lattice of G, then
has
levels.Proof: Follows from Theorem 3.1 where
for all
Theorem 3.3 If G is a cyclic group of order
where
are distinct primes and
is a subgroup lattice of G, then the number
of subgroups a
level of
is given by
Proof: For
the result is trivially true since the trivial group is the only subgroup at the first level and we have
Subgroups at the second level
are of the form
for
Since for each prime
there is a unique subgroup
of G, the total number of subgroups of this form is the number of ways of choosing (without repetition) one prime
from m primes. Hence there are
subgroups at the second level.Again, subgroups at the third level
are of the form
for
Since for each product
there is a unique subgroup
of G, the total number of subgroups of this form is the number of ways of choosing (without repetition) two primes
from m primes. Hence there are
subgroups.In a similar way, subgroups at the
level are generated by divisors of the form
Since there is a unique subgroup for each divisor of this form, we choose (without repetition)
primes
from
primes hence there are
subgroups at the
.Lemma 3.4 If G is a cyclic group of order
where
are distinct primes and
is a subgroup lattice of G, then for every subgroup H of G at
level, there are
chains towards
level.Proof: At the first level
there is only trivial group which is the subgroup of all m subgroups of the second level. But we also have
hence the result is true for
For
subgroups at the
level are of the form
Since G is cyclic, given two subgroups of G,
and
we have
iff
for
Since
and there are
distinct primes in the product
we remain with
choices of
Hence there are
subgroups of G at
level such that
Theorem 3.5: If G is a cyclic group of order
where
are distinct primes and
is a subgroup lattice of G, then the total number of chains
from
level to
level of
is given by
Proof: The number of chains from
level to
level is the product of the number of subgroups at
with the number of chains per subgroup from
level to
level. From Theorem 3.3 and Lemma 3.4, the number of chains from
level to
level of
is then given by
Theorem 3.6: If G is a cyclic group of order
where
are distinct primes and
is a subgroup lattice of G, then the number of ascending chains
from
to G is
Proof: From Lemma 3.4, the number of chains per subgroup from
level to
level is given by
To get the total number of ascending chains from the trivial subgroup to G is simply taking products of these numbers over all levels. It follows that,
Example 3.7: Let G be a cyclic group of order
here
The lattice of G is as shown below;![]() | Figure 1. The lattice of a cyclic group G |
This justifies Corollary 3.2.To justify Theorem 3.3 for the number of subgroups at each level, we use the following table.
|
as stated in Theorem 3.6. These chains are:
level of a lattice structure
of a cyclic group of order the product of m distinct primes is given by m combination
Furthermore, it was proved that the number of ascending chains of
is given by
In future work, we will study the lattice structure of cyclic groups of order the product of m prime powers. We will deduce general formulas for finding the number of subgroups at each level and number of ascending chain.